C program for base conversion

Aim: Base conversion of a number using C.

#include<stdio.h>
#include<conio.h>
#include<string.h>
void main()
{
	unsigned dec,t,d,i;
	char bin[20],oct[15],hex[5];
	printf("Enter a decimal number : ");
	scanf("%u",&dec);
	t=dec;
	i=0;
	do
	{
		d=t%2;
		t=t/2;
		bin[i++]=d+48;
	}while(t!=0);
	bin[i]='\0';
	strrev(bin);
	t=dec;
	i=0;
	do
	{
		d=t%8;
		t=t/8;
		oct[i++]=d+48;
	}while(t!=0);
	oct[i]='\0';
	strrev(oct);
	t=dec;
	i=0;
	do
	{
		d=t%16;
		t=t/16;
		if(d>9) hex[i++]=d+55;
		else hex[i++]=d+48;
	}while(t!=0);
	hex[i]='\0';
	strrev(hex);
	printf("\nBinary equivalent of %u is %s",dec,bin);
	printf("\nOctal equivalent of %u is %s",dec,oct);
	printf("\nHexadecimal equivalent of %u is %s",dec,hex);
}